1 00:00:01,350 --> 00:00:09,900 We are going to encode our code with detector operation, right, so the need for an inner circle is 2 00:00:10,740 --> 00:00:12,080 the most enduring tourists. 3 00:00:12,090 --> 00:00:18,660 This will have this Bindschadler, Churchill or any other circular pattern in their databases. 4 00:00:18,990 --> 00:00:21,390 And whenever this record has been. 5 00:00:24,030 --> 00:00:32,220 Written on the table, or if that has been executed on the commission designed to resist my triggering 6 00:00:32,220 --> 00:00:32,660 alarm. 7 00:00:32,970 --> 00:00:39,660 So the databases of those and others contain this pattern of the outer circle. 8 00:00:40,260 --> 00:00:48,210 So if we encode that circle, then it may be chances for some antivirus to help bypass. 9 00:00:50,040 --> 00:00:58,690 And we don't need to bypass every antivirus in the world, but we need to bypass only the software of 10 00:00:58,710 --> 00:00:59,510 the current system. 11 00:00:59,580 --> 00:00:59,990 Right. 12 00:01:02,490 --> 00:01:08,560 You know, if you are checking in with him or any testing in a crime organization, you need to know 13 00:01:08,560 --> 00:01:10,040 about what I noticed. 14 00:01:10,090 --> 00:01:15,310 There is obviously do not use every antivirus in the world, but there use one or two. 15 00:01:15,310 --> 00:01:15,630 Right. 16 00:01:16,000 --> 00:01:25,080 If your circle bypasses those two antivirus software, then you will obviously will win the game. 17 00:01:25,120 --> 00:01:33,220 Right now, I have a picture of the current president I shall call visible when I am anchoring with 18 00:01:33,220 --> 00:01:35,630 this Shakoor. 19 00:01:35,710 --> 00:01:38,610 I have got some issues because of this rash X. 20 00:01:38,800 --> 00:01:44,260 It's representing disaster as a matter of course it should represent. 21 00:01:44,260 --> 00:01:48,210 But some characters are turning into Unicode characters. 22 00:01:48,670 --> 00:01:50,070 That's what I heard on this. 23 00:01:51,350 --> 00:01:55,750 I am going to replace this Brack's backslash with null. 24 00:01:56,470 --> 00:01:56,860 I won't. 25 00:01:56,920 --> 00:02:01,820 I'm going to remove this backsliders so don't worry. 26 00:02:01,820 --> 00:02:07,840 Yes, we get the circle in line for my country. 27 00:02:08,740 --> 00:02:10,720 OK, this is our thing now. 28 00:02:10,720 --> 00:02:13,580 We need to remove the X right there. 29 00:02:13,630 --> 00:02:18,370 We know there is no X in the hexadecimal system, no system. 30 00:02:18,370 --> 00:02:21,130 Right CareMore X. 31 00:02:21,130 --> 00:02:25,990 We need to look for this and telescreen to do that so far. 32 00:02:27,160 --> 00:02:31,510 OK, first we will make the string. 33 00:02:31,510 --> 00:02:38,290 In order to do that, there is a function that's a hex underscore Dom is equal to. 34 00:02:41,460 --> 00:02:42,120 This toucher. 35 00:02:47,160 --> 00:02:48,720 So if I put in that accident. 36 00:02:53,690 --> 00:02:59,200 Now, I look at each and every character in the new element of every stripe. 37 00:02:59,630 --> 00:03:07,270 Now we can just simply look over it and remove the eggs for I in the hexagram. 38 00:03:11,370 --> 00:03:25,920 If I is equal, is equal to X, then we need to say X dump the rule of it right now. 39 00:03:25,980 --> 00:03:30,900 Let me cut this statement and pasted in here. 40 00:03:31,320 --> 00:03:33,630 Now we can see there is no X. 41 00:03:36,010 --> 00:03:42,250 Perfect, there is 31 C0 and I get 31 and be perfect. 42 00:03:42,890 --> 00:03:45,280 Now, why do we need to join? 43 00:03:47,660 --> 00:03:51,470 We need to join these two elements as one singular. 44 00:03:52,770 --> 00:03:59,580 It's spring and these two are single spring, and these two, as soon as she saw the output should be 45 00:03:59,580 --> 00:04:00,170 31. 46 00:04:00,690 --> 00:04:09,070 Come on, come on, baby, that and 31 on and so on up to this last twenty eight. 47 00:04:10,020 --> 00:04:18,240 So we need to just concatenate these two or append these two characters into one thing to do that let's 48 00:04:19,170 --> 00:04:33,260 we are going to cover us and we're going to report the I in now we loop or this range of come up and 49 00:04:33,440 --> 00:04:33,930 Lentulov. 50 00:04:34,080 --> 00:04:34,740 Hextall. 51 00:04:36,020 --> 00:04:45,440 And I will skip two characters because in one step I happened, all those two characters say so the 52 00:04:45,500 --> 00:04:47,300 system is equal to. 53 00:04:49,460 --> 00:04:59,000 I'm going to use the joint matter joint of this joint will joint the two characters specified in the 54 00:04:59,000 --> 00:04:59,500 argument. 55 00:04:59,990 --> 00:05:02,060 So hex dump of. 56 00:05:03,700 --> 00:05:07,270 I used to I pressed to see what this. 57 00:05:09,100 --> 00:05:16,020 I used three and I press one is one and it was exclusive. 58 00:05:16,330 --> 00:05:25,600 So I guess I used to Hyperscore means when I used it becomes ectomorph zero is to do so in least it 59 00:05:25,600 --> 00:05:27,600 is one element. 60 00:05:28,000 --> 00:05:33,160 So we won't take two as into consideration because it is crazy. 61 00:05:34,510 --> 00:05:41,410 So ministry one minute one and we are going to join this into the template. 62 00:05:42,070 --> 00:05:46,830 Now I just simply a start up end of camp. 63 00:05:49,060 --> 00:05:52,720 Now, if I put into this, as we shall see. 64 00:05:54,470 --> 00:05:56,080 Correct me, commentor this one. 65 00:05:58,300 --> 00:06:07,210 So if I just let you get this, OK, we have got exactly Fastback in one street and second in second 66 00:06:07,510 --> 00:06:09,730 and third debate in the third place. 67 00:06:09,730 --> 00:06:19,480 Right now, what we're going to do is we are going to take a first bite and then we are going to start 68 00:06:19,480 --> 00:06:22,990 with a bite given in their input. 69 00:06:23,500 --> 00:06:28,570 So we have value is equal to the input of. 70 00:06:37,620 --> 00:06:44,910 So here we give the input and it will be stored in a value variable, that input will be provided and 71 00:06:44,910 --> 00:06:53,010 that by the expert with each byte in this circle and then the output, the circle. 72 00:06:54,520 --> 00:07:01,990 So here there is one problem if you exclude the same bike, you're getting out of it, right? 73 00:07:05,660 --> 00:07:13,940 We are using the scumbag's and the previous use to get rid of the content suffix and its content Norbert's 74 00:07:14,240 --> 00:07:22,740 so in the same way we need to enter a value that is not in this code already, because if there is to 75 00:07:22,830 --> 00:07:29,300 C0, then if we exclude c0 common C0, then you get the resultant Circo. 76 00:07:29,960 --> 00:07:38,690 How the nailbiter displays and the strong opposition parties decide to remove this and it will just 77 00:07:38,690 --> 00:07:41,140 ignore all this content after that nabay. 78 00:07:41,690 --> 00:07:49,340 So that's what we need to check the value, whether it's in Chalco or not. 79 00:07:49,760 --> 00:07:51,950 To do that we need to see if. 80 00:07:53,930 --> 00:07:55,550 Value in charcoaled. 81 00:07:59,100 --> 00:08:06,870 So just to separate, OK, the value is in already charcoaled, we need to ask again, right? 82 00:08:07,950 --> 00:08:12,030 I mean, you need to take the input again with different, but. 83 00:08:17,240 --> 00:08:20,330 So it's a it is already initial to the. 84 00:08:29,970 --> 00:08:32,550 So you want to sound right? 85 00:08:32,940 --> 00:08:37,650 I'm going to copy this one, I'm going to put it in here. 86 00:08:40,440 --> 00:08:45,990 So, again, we'll ask for the user input, and that will be widely available. 87 00:08:46,710 --> 00:08:47,150 All right. 88 00:08:47,160 --> 00:08:52,860 Now we have got this where you saw this value and our interest. 89 00:08:53,460 --> 00:09:04,590 And in that, we need to loop over each element so that so far I in s we need to certain physicals to 90 00:09:05,400 --> 00:09:13,110 know we want to convert this to turn into integer and this bit into integer and that we need to do or. 91 00:09:14,870 --> 00:09:26,240 So to convert the hexadecimal in to integer into Ikoma 16 and the saw operation in Python is this is 92 00:09:26,240 --> 00:09:32,420 chapter marker, just cap and tax value, comma 16. 93 00:09:34,170 --> 00:09:41,640 So we are changing the hexadecimal representations in two integers and performing the exact operation 94 00:09:42,090 --> 00:09:47,640 that's Encoder Shirker or just the result. 95 00:09:50,500 --> 00:09:56,350 And I'm going to take that notion, so I'm going to appeal this very similar this result with. 96 00:10:01,040 --> 00:10:06,920 I'm sorry, I did not do one thing, so what I want to do is we need to convert this into hexadecimal 97 00:10:06,920 --> 00:10:09,350 format and to. 98 00:10:10,320 --> 00:10:11,360 Haqq subcamp. 99 00:10:15,510 --> 00:10:16,440 So no. 100 00:10:18,350 --> 00:10:26,180 What has been committed here and then we cannot get the result of into the exodus and then we opened 101 00:10:26,180 --> 00:10:26,860 it to the street. 102 00:10:28,340 --> 00:10:30,870 Now let's go and bring this result. 103 00:10:35,580 --> 00:10:39,270 So let's go and execute our script. 104 00:10:39,690 --> 00:10:41,940 No, I learned to do that, but yeah. 105 00:10:47,860 --> 00:10:56,350 So, yes, we have got this charcoaled you can see Droits nine six tonight and we OK find no we don't 106 00:10:56,350 --> 00:11:05,150 want do X, so that's this one and each consists of. 107 00:11:05,180 --> 00:11:10,070 So we need to avoid that is jewelries. 108 00:11:10,660 --> 00:11:15,700 And actually the second element in that screen and when you say to you. 109 00:11:16,030 --> 00:11:20,450 So from that element onwards we are we want to happen to the result. 110 00:11:21,130 --> 00:11:25,150 So let's let's run our script and execute year. 111 00:11:25,990 --> 00:11:32,170 And they realize we have got exactly nine B sixty six year, nine one nine B, etc.. 112 00:11:32,680 --> 00:11:37,290 So let's also put six. 113 00:11:37,990 --> 00:11:43,440 I'm putting the All Blacks rush to escape this backslash special value. 114 00:11:44,200 --> 00:11:51,480 So let's run this year and then realize this is our uncoded circle. 115 00:11:52,330 --> 00:11:56,220 Now we need to check whether our result is character. 116 00:11:56,860 --> 00:12:04,300 So open the calculator or to at least take the first bite of the ordinary circuit, which is 31. 117 00:12:04,570 --> 00:12:11,650 So I go to hexadecimal and then take the first word of circle, which is 31 31, and I'm going to ignore 118 00:12:11,710 --> 00:12:11,930 it. 119 00:12:12,820 --> 00:12:15,380 So what we have input this year. 120 00:12:15,480 --> 00:12:19,920 You know, if you hit enter, you get the 90, which is the first. 121 00:12:19,930 --> 00:12:32,560 But in the similar case, you can check the which is C zero G zero X are you and you get the value Cixi 122 00:12:33,760 --> 00:12:40,510 so that this is our required and codeshare when we have done the Exaro operation between each byte shall 123 00:12:40,510 --> 00:12:43,090 call with the input value.