1 00:00:00,990 --> 00:00:08,090 Now, in this video, I'm going to explain how to convert the small number to the binary number superstar 2 00:00:08,180 --> 00:00:12,570 to explain the process, then we will move on to the example first, the processes. 3 00:00:12,900 --> 00:00:20,460 If you want to convert decimal number to any base format, you need to divide that number with this 4 00:00:20,460 --> 00:00:20,970 base. 5 00:00:22,050 --> 00:00:25,920 Since binary is a base to we need to divide this this month with the two. 6 00:00:26,550 --> 00:00:30,630 And what you want to do is you need to keep track of quotient and domantas. 7 00:00:31,020 --> 00:00:39,360 So after Bujon operation you will get the question backgrounder and the next step you take that concept. 8 00:00:39,360 --> 00:00:46,890 And again, the way to do it, this base number, which is two, and then you get the question negroland, 9 00:00:47,190 --> 00:00:52,470 I repeat the same process of the word in the question until you get the question to zero. 10 00:00:53,520 --> 00:01:02,460 And then the binary number from is the the miners are two miners who just append the reminders and that 11 00:01:02,460 --> 00:01:03,160 is Urban-Rural. 12 00:01:03,180 --> 00:01:07,180 But of course, now that's an example so that you can get some clarity. 13 00:01:07,500 --> 00:01:11,250 I'm going to take an example of fight with the decimal number. 14 00:01:11,970 --> 00:01:18,330 And if we were to wait, too, because we are converting to the base two, which is binary. 15 00:01:18,690 --> 00:01:20,670 So we are going to convert this divide. 16 00:01:20,970 --> 00:01:25,750 And two binary so divided with two, we get the question, that's 27. 17 00:01:25,800 --> 00:01:30,180 And when there is one who goes to the condition, it's 54 plus one. 18 00:01:31,530 --> 00:01:39,210 And you take this question and they endured it with two, you get on by two, you get questioned astatine 19 00:01:39,210 --> 00:01:46,230 and as one and you again repeat the same process by taking questions 13 and wearing it with two. 20 00:01:46,710 --> 00:01:49,320 And you get the question at six and under one. 21 00:01:50,490 --> 00:01:54,520 So do the same process until you get the question to zero. 22 00:01:54,780 --> 00:02:00,090 So it's even if we further do it, we get the remainder. 23 00:02:01,110 --> 00:02:04,000 So it's not much needed. 24 00:02:04,350 --> 00:02:06,860 So we have considered our version. 25 00:02:06,880 --> 00:02:08,360 So what is Auburndale put? 26 00:02:08,520 --> 00:02:15,180 It means that if you see the two minus one one one zero one one, you just append all these bits and 27 00:02:15,180 --> 00:02:15,690 reverse it. 28 00:02:15,870 --> 00:02:22,490 Or you can just fall from the bottom to top and just append those bits. 29 00:02:22,800 --> 00:02:26,610 So the other binary number will be one one zero one one one. 30 00:02:27,240 --> 00:02:35,100 And that is our required one, because you just take is one number and work with the base of the destination 31 00:02:35,100 --> 00:02:35,580 formic. 32 00:02:35,820 --> 00:02:45,110 And then you take the question and again, divided and the result not all that will be the reversing 33 00:02:45,390 --> 00:02:46,890 reverse of this demanders. 34 00:02:47,550 --> 00:02:51,840 One one zero one one one is a binary format of the number of different.